[Gambas-user] To the wish list...

Dimitris Anogiatis dosida at ...626...
Sat Aug 22 12:46:46 CEST 2009


Benoît,

Perhaps you could also enhance Find to accept regular expressions (or
something similar to what we can use with LIKE)

If it already does can you provide some more documentation about it in
Gambasdoc?


Regards
Dimitris

2009/8/22 Benoît Minisini <gambas at ...1...>

> > Jussi Lahtinen ha scritto:
> > > Meaning like this? Should be faster!
> > >
> > > Dim col As New Collection
> > >
> > > For ii = 0 To iMyArray.Max
> > > col.Add(iMyArray[ii],  iMyArray[ii])
> > > Next
> > >
> > > iMyArray.Clear()
> > >
> > > For Each ii In col
> > > iMyArray.Add(ii)
> > > Next
> > >
> > >
> > > Jussi
> > >
> > > 2009/8/21 Benoît Minisini <gambas at ...1...>:
> > >>> Now I use algorithm like this (maybe not optimal);
> > >>>
> > >>> Dim ii As Integer
> > >>> Dim jj As Integer
> > >>> Dim bRemove As Boolean
> > >>>
> > >>> While ii < iMyArray.Count
> > >>>
> > >>>  jj = 0
> > >>>  bRemove = False
> > >>>  While jj < iMyArray.Count
> > >>>   If ii <> jj And iMyArray[ii] = iMyArray[jj] Then
> > >>>   iMyArray.Remove(ii)
> > >>>   bRemove = True
> > >>>   Else
> > >>>   Inc jj
> > >>>   Endif
> > >>>  Wend
> > >>>
> > >>> If bRemove = False Then
> > >>> Inc ii
> > >>> Endif
> > >>> Wend
> > >>>
> > >>>
> > >>> Good point Benôit. Array is populated from file, but maybe I should
> use
> > >>> .Find() before .Add().
> > >>>
> > >>>
> > >>> Jussi
> > >>
> > >> You should use a collection to detect duplicates, otherwise your
> > >> algorithm is O(n^2)
> >
> > Another technique could be to keep the array (or collection, don't know)
> > sorted while constructing it. If sorted, a single run can detect all the
> > duplicates, giving O(n). If the logic behind requires the values in the
> > original order, then this information should be kept in a parallel array.
> >
> > Just for fun...
> >
> > Regards,
> > Doriano
> >
>
> Yes. I wanted to add two methods: AddSorted() and FindSorted(), that will
> assume the array is sorted, and so will be fastest.
>
> Regards,
>
> --
> Benoît
>
>
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