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Re: float-integer error with \
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- Subject: Re: float-integer error with \
- From: Bruce Steers <bsteers4@xxxxxxxxx>
- Date: Tue, 22 Apr 2025 19:52:13 +0100
- To: user@xxxxxxxxxxxxxxxxxxxxxx
On Tue, 22 Apr 2025 at 19:15, Benoît Minisini < benoit.minisini@xxxxxxxxxxxxxxxx> wrote: > Le 22/04/2025 à 18:46, Bruce Steers a écrit : > > Appologies I guess the error is mine. > > vbSize is a SpinBox and .Value returns a Float. > > I did not try iSize = (CInt(vbSize.Value) \ 3) * 3 :-\ > > > > I'm sure the code worked when i wrote it though. > > > > Respects > > BruceS > > > > In master, SpinBox has been enhanced to support floating point values > (and other new features). So now its Value property returns a Float, > which cannot be handled by '\'. > > By the way, I don't remember why '\' and 'MOD' cannot automatically > convert floating points into integers, like the other operators. I see > no reason at the moment. > > Regards, > > -- > Benoît Minisini. Aah I see now, cheers. Yeah I would have thought \ would convert to Integer as surely it only really returns an integer and cannot return a float? Respects BruceS
float-integer error with \ | Bruce Steers <bsteers4@xxxxxxxxx> |
Re: float-integer error with \ | Bruce Steers <bsteers4@xxxxxxxxx> |
Re: float-integer error with \ | Benoît Minisini <benoit.minisini@xxxxxxxxxxxxxxxx> |